4.9t^2+350t+2400=0

Solution for 4.9t^2+350t+2400=0 equation:

4.9t^2+350t+2400=0

a = 4.9; b = 350; c = +2400;
Δ = b2-4ac
Δ = 3502-4·4.9·2400
Δ = 75460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{75460}=\sqrt{196*385}=\sqrt{196}*\sqrt{385}=14\sqrt{385}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(350)-14\sqrt{385}}{2*4.9}=\frac{-350-14\sqrt{385}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(350)+14\sqrt{385}}{2*4.9}=\frac{-350+14\sqrt{385}}{9.8}
$